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Python 判断质数函数

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发表于 2022-4-25 22:10:28 | 显示全部楼层
你可以试试numpy,这个库底层用c写的,运行效率高
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发表于 2022-4-26 15:42:47 | 显示全部楼层
test

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发表于 2022-4-26 20:22:32 | 显示全部楼层
Manners maketh man

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发表于 2022-12-26 00:20:50 | 显示全部楼层
xiaomeng 发表于 2022-4-24 18:57
你想复杂了
[mw_shl_code=python,true]

循环到小于等于根号n的最大整数就行

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发表于 2023-1-14 15:31:51 | 显示全部楼层
本帖最后由 wwwab 于 2023-1-14 16:00 编辑

我的码风是这个样子的:

[Python] 纯文本查看 复制代码
n=float(input("Please enter the number here:"))
m=int(n)
a=n.is_integer()
if m>=0 and a==True:    #It means the number what the user entered is a nonnegative integer number, namely a natural number, and a necessary condition for a number to be a prime number is that the number to be a natural number.
    if m<2:
        print("False. The number you entered is:",str(m)," . Congratulations! It means it is not a prime number and it is a composite number.")
    elif m==2:
        print("True. The number you entered is:",str(m)," . Congratulations! It means it is a prime number.")
    else:
        for i in range(2, m):
            if m%i==0:
                print("False. The number you entered is:",str(m)," . Congratulations! It means it is not a prime number and it is a composite number.")
                break
            else:
                print("True. The number you entered is:",str(m)," . Congratulations! It means it is a prime number.")
elif m<0:
    print("False. Warning:The number you entered is:",str(m)," . What you entered is not an nonnegative number, it is a negative number, It does not belong to a natural number, nor can it belong to a prime number. Please try again!")
else:
    print("False. Warning:The number you entered is:",str(m)," . What you entered is not an integer number, It does not belong to a natural number, nor can it belong to a prime number. Please try again!")    #It means a==False



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发表于 2023-1-14 19:09:18 | 显示全部楼层
wwwab 发表于 2023-1-14 15:31
我的码风是这个样子的:

[mw_shl_code=python,true]n=float(input("Please enter the number here:"))

可以,,,,
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发表于 2024-3-1 23:14:44 | 显示全部楼层
应该是这样:
[Python] 纯文本查看 复制代码
# coding=utf-8

number = int(input(“请输入正整数:”))
if number <= 0:
    print(“请输入正整数。”)
else:
    for i in range(number):
        if number % (i + 1) == 0:
            continue
        else:
            break
        
print(“这是个质数。”)
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